JEE Main levelSingle correct optionDifficulty 2 of 3df061
Given E∘(CuX+/Cu)=+0.52V and E∘(CuX2+/CuX+)=+0.16V, which statement about CuX+ in aqueous solution at 298 K (standard conditions) is correct?
AIt is stable because Ecell∘ for disproportionation is −0.36V
BIt disproportionates to CuX2+ and Cu with Ecell∘=+0.36V
CIt disproportionates with Ecell∘=+0.68V
DIt disproportionates with Ecell∘=+0.16V
Answer: B
For 2CuX+→CuX2++Cu, CuX+ is reduced at the cathode (0.52V) and oxidised at the anode (0.16V). Ecell∘=0.52−0.16=+0.36V>0, so the reaction is spontaneous and CuX+ is unstable in water.