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JEE Advanced levelSingle correct optionDifficulty 3 of 3df041

Match the neutral gaseous atom (ground state) in List I with its spin-only magnetic moment in List II. List I: (P) $Z = 24$ , (Q) $Z = 25$ , (R) $Z = 26$ , (S) $Z = 29$ . List II: (1) $1.73 BM$ , (2) $4.90 BM$ , (3) $5.92 BM$ , (4) $6.93 BM$ .

AP-4, Q-3, R-2, S-1
BP-3, Q-4, R-2, S-1
CP-4, Q-2, R-3, S-1
DP-4, Q-3, R-1, S-2

Answer: A

Cr (

3 d^{5} 4 s^{1}

) has 6 unpaired, 6.93 BM; Mn (

3 d^{5} 4 s^{2}

) has 5, 5.92 BM; Fe (

3 d^{6} 4 s^{2}

) has 4, 4.90 BM; Cu (

3 d^{10} 4 s^{1}

) has 1, 1.73 BM. Hence P-4, Q-3, R-2, S-1.

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