Match the carbonyl (List I) with its geometry and metal hybridisation (List II). List I: P Ni(CO)4; Q Fe(CO)5; R Cr(CO)6; S Mn2(CO)10. List II: 1 tetrahedral, sp^3; 2 trigonal bipyramidal, dsp^3; 3 octahedral, d^2sp^3; 4 contains a metal-metal bond and no bridging CO.

JEE Main levelSingle correct optionDifficulty 2 of 3cc193

Match the carbonyl (List I) with its geometry and metal hybridisation (List II). List I: P $Ni (CO) X_{4}$ ; Q $Fe (CO) X_{5}$ ; R $Cr (CO) X_{6}$ ; S $Mn X_{2} (CO) X_{10}$ . List II: 1 tetrahedral, $s p^{3}$ ; 2 trigonal bipyramidal, $d s p^{3}$ ; 3 octahedral, $d^{2} s p^{3}$ ; 4 contains a metal-metal bond and no bridging CO.

Ni (CO) X_{4}

is tetrahedral (

s p^{3}

Fe (CO) X_{5}

is trigonal bipyramidal (

d s p^{3}

Cr (CO) X_{6}

is octahedral (

d^{2} s p^{3}

Mn X_{2} (CO) X_{10}

has a Mn-Mn bond with ten terminal

CO

. So P-1, Q-2, R-3, S-4.