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JEE Main levelSingle correct optionDifficulty 2 of 3cc078

The oxidation state and coordination number of chromium in $[Cr (en) X_{2} (C X_{2} O X_{4})] X^{+}$ are respectively (en is neutral and bidentate; oxalate is $2 -$ and bidentate)

A+3 and 3
B+5 and 6
C+3 and 6
D+1 and 6

Answer: C

Charge:

x + 0 + (- 2) = + 1

gives

x = + 3

. Donor atoms: two en give 4 and one oxalate gives 2, a total of 6.

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