Answer: B
The cation is [Co(NHX3)X6]Xn+ and the anion is [Cr(CN)X6]Xn−, and the two charges must cancel. NH3 is neutral, so n is the oxidation state of Co. For the anion x−6=−n gives Cr = 6−n. Equal charges with n=3 give Co(III) and Cr(III) (the common state of both). The cation is named first and the anion ends in -ate.