JEE Main levelSingle correct optionDifficulty 2 of 3ck166
For AB the forward activation energy is 90kJmol−1 and ΔH=+30kJmol−1. A catalyst lowers the forward activation energy to 70kJmol−1. The activation energy of the reverse reaction in the catalysed route, in kJmol−1, is
A40
B60
C100
D−10
Answer: A
ΔH=Ea,f−Ea,r holds for both routes since ΔH is unchanged by a catalyst. So Ea,r=70−30=40kJmol−1 (the uncatalysed value is 60).