Two parallel first-order reactions of A, giving B and C, have the same pre-exponential factor. Their activation energies are $60.0$ and $65.0 kJ mo l^{- 1}$ respectively. Find $k_{B} / k_{C}$ at $300 K$ ( $R = 8.314 J mo l^{- 1} K^{- 1}$ ), to two decimal places.

Numerical answer type, tolerance 0.02.

Answer: 7.42

With equal

A

factors,

k_{B} / k_{C} = exp [(E_{C} - E_{B}) / RT]

. The exponent is

5000/ (8.314 \times 300) = 2.0047

, so

k_{B} / k_{C} = e^{2.0047} = 7.42