A plot of $\ln k$ against $1/T$ is linear with slope $-5000$ K and intercept 18 ($k$ in ${\mathrm{s}}^{-1}$). Use $R=8.314\mathrm{J}\mathrm{mo}{\mathrm{l}}^{-1}{\mathrm{K}}^{-1}$, $e^{18}=6.57\times 10^7$, $e^8=2981$. Which statements are correct?

1. A$k$ at 250 K is about 0.135 ${\mathrm{s}}^{-1}$ ($e^{-2}=0.1353$)
2. B$A=6.57\times 10^7{\mathrm{s}}^{-1}$
3. C$k$ at 500 K is about 2981 ${\mathrm{s}}^{-1}$
4. D$E_a=95.7\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$