A reaction has E_a=60 kJ mol^-1 and k=2.0x10^-3 s^-1 at 300 K. Using R=8.314 J mol^-1K^-1, the rate constant at 320 K, in s^-1, is

JEE Main levelSingle correct optionDifficulty 2 of 3ck133

A reaction has $E_{a} = 60 kJ mo l^{- 1}$ and $k = 2.0 \times 1 0^{- 3} s^{- 1}$ at 300 K. Using $R = 8.314 J mo l^{- 1} K^{- 1}$ , the rate constant at 320 K, in $s^{- 1}$ , is

ln \frac{k _{2}}{k _{1}} = \frac{E _{a}}{R} (\frac{1}{T _{1}} - \frac{1}{T _{2}}) = \frac{60000}{8.314} (0.000208) = 1.503

, so

k_{2} / k_{1} = 4.50

and

k_{2} = 8.99 \times 1 0^{- 3} s^{- 1}