JEE Advanced levelNumerical answerDifficulty 3 of 3ce215
At a total pressure of 1.0atm, NX2OX4(g) is 20\% dissociated at 300K and 50\% dissociated at 350K (equilibrium NX2OX4(g)2NOX2(g)). Assuming ΔH is constant and R=8.314Jmol−1K−1, find ΔH in kJ/mol to the nearest integer.
Numerical answer type, answer in kJ/mol, tolerance 0.5.
Answer: 36 kJ/mol
Kp=4α2P/(1−α2): Kp1=0.1667, Kp2=1.3333 atm. ΔH=Rln(Kp2/Kp1)/(1/300−1/350)=8.314×2.0794/0.000476=36.31 kJ/mol, i.e. 36.