JEE Advanced levelNumerical answerDifficulty 3 of 3ce216
One mole of NX2OX4 is kept at a constant total pressure of 1.0atm and constant temperature where Kp=0.50atm for NX2OX4(g)2NOX2(g). How many moles of an inert gas must be mixed in so that the degree of dissociation of NX2OX4 becomes 0.40? Give the answer to two decimal places.
Numerical answer type, answer in mol, tolerance 0.02.
Answer: 0.73 mol
With x mol inert gas: NX2OX40.60, NOX20.80, total N=1.40+x. Kp=(0.80/N)2P/[(0.60/N)]=0.64P/(0.60N). So N=0.64/(0.60×0.50)=2.1333 and x=N−1.40=0.7333 mol, i.e. 0.73.