For CaCO3(s) CaO(s) + CO2(g), K_p = 0.80 atm at 1100 K. A rigid 5.0 L vessel at 1100 K contains solid CaCO3 and CaO together with some CO2 (ideal gas). The CaCO3 does not decompose at all if the amount of CO2 is at least a minimum value. Find this minimum amount in millimoles (nearest integer). Use R = 0.0821 L atm mol^-1 K^-1.

JEE Advanced levelNumerical answerDifficulty 3 of 3ce151

For $CaCO X_{3} (s) CaO (s) + CO X_{2} (g)$ , $K_{p} = 0.80$ atm at $1100 K$ . A rigid $5.0 L$ vessel at $1100 K$ contains solid $CaCO X_{3}$ and $CaO$ together with some $CO X_{2}$ (ideal gas). The $CaCO X_{3}$ does not decompose at all if the amount of $CO X_{2}$ is at least a minimum value. Find this minimum amount in millimoles (nearest integer). Use $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ .

Numerical answer type, answer in mmol, tolerance 1.

No decomposition requires

Q_{p} = p_{CO X_{2}} \geq K_{p}

(otherwise the reaction would go forward).

n = p V / RT = (0.80) (5.0) / (0.0821 \times 1100) = 0.04429

mol

= 44.29

mmol, i.e. 44 mmol.