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Relation between Kp and Kc, units
JEE Main level
Single correct option
Difficulty 2 of 3
ce068
For
2
SO
X
2
(
g
)
+
O
X
2
(
g
)
2
SO
X
3
(
g
)
,
K
p
=
0.040
at
m
−
1
at 800 K. Using
R
=
0.0821
L
atm
mo
l
−
1
K
−
1
, the value of
K
c
in
L
mo
l
−
1
is
A
0.040
B
6.1
×
1
0
−
4
C
173
D
2.63
Answer: D
Δ
n
=
−
1
, so
K
p
=
K
c
(
RT
)
−
1
and
K
c
=
K
p
RT
.
RT
=
0.0821
×
800
=
65.7
, so
K
c
=
0.040
×
65.7
=
2.63
L
mo
l
−
1
.
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