For $N X_{2} O X_{4} (g) 2 NO X_{2} (g)$ at 298 K, $K_{c} = 5.8 \times 1 0^{- 3} mol L^{- 1}$ . Using $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ , calculate $K_{p}$ in atm, correct to two decimal places.

Numerical answer type, answer in atm, tolerance 0.01.

Answer: 0.14 atm

Δ n = 2 - 1 = + 1

, so

K_{p} = K_{c} RT = 5.8 \times 1 0^{- 3} \times 0.0821 \times 298 = 0.1419

atm, which is 0.14 atm to two decimals.