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NEET levelSingle correct optionDifficulty 1 of 3ce060

For $PCl X_{5} (g) PCl X_{3} (g) + Cl X_{2} (g)$ , $K_{c} = 0.040 mol L^{- 1}$ at 500 K. Taking $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ , $K_{p}$ (in atm) is approximately

A $67$
B $1.64$
C $9.7 \times 1 0^{- 4}$
D $0.040$

Answer: B

Δ n = + 1

, so

K_{p} = K_{c} RT = 0.040 \times 0.0821 \times 500 = 1.64

atm.

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