JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ce044
1.0 mol of PClX5(g) dissociates (PClX5(g)PClX3(g)+ClX2(g)) to the extent of 50% at a total equilibrium pressure of 1.00 atm and temperature T. Which statements are correct?
AKp=0.333 atm at T
BThe mole fraction of PClX5 at equilibrium is 0.50
CAt the same T and a total pressure of 4.00 atm, the degree of dissociation is about 0.28
DAt the same T and a total pressure of 4.00 atm, the degree of dissociation is exactly 0.25
Answer: A, C
Kp=α2P/(1−α2)=0.25/0.75=0.333 atm, so (A) is true. The mole fraction of PClX5 is (1−α)/(1+α)=0.333, not 0.50, so (B) is false. At 4.00 atm, α=Kp/(Kp+P)=0.333/4.333=0.277, so (C) is true; halving is not exact, so (D) is false.