JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ce043
For HX2(g)+IX2(g)2HI(g), Kc=50 at a given temperature. Four mixtures are prepared in vessels at this temperature. A mixture with Qc=Kc is already at equilibrium and shows no net reaction. In which mixtures will the net reaction proceed in the backward direction (towards HX2 and IX2)?
A[HX2]=0.10, [IX2]=0.10, [HI]=1.00 (all in M)
B[HX2]=0.20, [IX2]=0.20, [HI]=1.00 (all in M)
C[HX2]=0.05, [IX2]=0.10, [HI]=0.50 (all in M)
D[HX2]=0.04, [IX2]=0.05, [HI]=0.80 (all in M)
Answer: A, D
Compute Qc=[HI]2/([HX2][IX2]): (A) 100, (B) 25, (C) 50, (D) 320. Backward reaction needs Qc>Kc=50, which holds for (A) and (D). (B) goes forward and (C) is at equilibrium.