For 2SO2(g) + O2(g) 2SO3(g), K_c = 40 L mol^-1 at a given temperature. An equilibrium mixture is disturbed by adding O2 at constant volume and temperature. At the new equilibrium [O2] = 0.25 M. The new ratio [SO3]/[SO2] is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ce045

For $2 SO X_{2} (g) + O X_{2} (g) 2 SO X_{3} (g)$ , $K_{c} = 40 L mo l^{- 1}$ at a given temperature. An equilibrium mixture is disturbed by adding $O X_{2}$ at constant volume and temperature. At the new equilibrium $[O X_{2}] = 0.25 M$ . The new ratio $[SO X_{3}] / [SO X_{2}]$ is

From

K_{c} = [SO X_{3}]^{2} / ([SO X_{2}]^{2} [O X_{2}])

([SO X_{3}] / [SO X_{2}])^{2} = K_{c} [O X_{2}] = 40 \times 0.25 = 10.0

. Taking the square root, the ratio is

3.162