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NEET levelSingle correct optionDifficulty 1 of 3cb060

Within a layer of graphite, every carbon atom is hybridised as

A $s p$
B $s p^{3} d$
C $s p^{2}$
D $s p^{3}$

Answer: C

Each carbon forms three sigma bonds with neighbouring carbons, which needs three hybrid orbitals. These are

s p^{2}

orbitals; the fourth electron sits in the unhybridised p orbital and gives the delocalised pi cloud.

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