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JEE Main levelSingle correct optionDifficulty 2 of 3cb063

The hybridisation of the central atom in $NO X_{2} X^{+}$ , $NO X_{3} X^{-}$ and $NH X_{4} X^{+}$ , in this order, is

A $s p^{2}, s p^{2}, s p^{3}$
B $s p, s p^{2}, s p^{2}$
C $s p, s p^{3}, s p^{3}$
D $s p, s p^{2}, s p^{3}$

Answer: D

Count sigma bonds plus lone pairs on the central atom.

NO X_{2} X^{+}

has 2 (linear,

s p

),

NO X_{3} X^{-}

has 3 (trigonal planar,

s p^{2}

) and

NH X_{4} X^{+}

has 4 (

s p^{3}

).

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