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NEET levelSingle correct optionDifficulty 1 of 3cb058

Boron in $BF X_{3}$ uses hybrid orbitals of the type

A $s p^{2}$
B $s p^{3} d$
C $s p^{3}$
D $s p$

Answer: A

Boron has three sigma bonds and no lone pair, so three hybrid orbitals are required. One s and two p orbitals give three

s p^{2}

orbitals directed to the corners of a triangle, so

BF X_{3}

is trigonal planar.

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