Answer: A, B, D
Four terminal hydrogens form 2c-2e bonds and two bridging hydrogens form 3c-2e banana bonds. The bridging B-H distance (about 133 pm) exceeds the terminal one (about 119 pm). The two bridging H atoms lie above and below the plane containing the 2 B and 4 terminal H atoms, so the six H atoms are not coplanar.