Answer: B, C, D
I: S has 1 bond and 3 lone pairs (−1), C is 0, N has a triple bond and one lone pair (0), so the first statement is false. II: S 0, C 0, N has 2 bonds and 2 lone pairs (5−4−2=−1) is true. III: S has 3 bonds, 1 lone pair (+1), N has 1 bond, 3 lone pairs (−2), C 0: true. Each sums to the ion charge −1.