Benzene is acetylated with CH3COCl/anhydrous AlCl3 to give P. P is treated with NaOCl/NaOH and then acidified to give Q. Q is warmed with SOCl2 to give R. R is

JEE Advanced levelSingle correct optionDifficulty 3 of 3co131

Benzene is acetylated with $CH X_{3} COCl$ /anhydrous $AlCl X_{3}$ to give P. P is treated with $NaOCl$ / $NaOH$ and then acidified to give Q. Q is warmed with $SOCl X_{2}$ to give R. R is

Friedel-Crafts acylation gives P =

C X_{6} H X_{5} COCH X_{3}

. The haloform reaction gives Q = benzoic acid,

C X_{6} H X_{5} COOH

(with

CHCl X_{3}

). Thionyl chloride converts

- COOH

- COCl

, so R is benzoyl chloride,

C X_{6} H X_{5} COCl