JEE Main levelOne or more correct optionsDifficulty 2 of 3co127
Butan-2-one is treated with excess NaOCl in aqueous NaOH and the mixture is then acidified. Which statements are correct?
APropanoic acid is formed
BChloroform is formed
CEthanoic acid is formed
DThe acid formed has one carbon atom less than the starting ketone
Answer: A, B, D
CHX3CHX2COCHX3 is a methyl ketone, so the CHX3 is lost as CHClX3 and the rest becomes CHX3CHX2COOX−, giving propanoic acid (3 carbons versus 4 in the ketone) on acidification. Ethanoic acid is not formed.