Ethanol, 4.6 g, is treated with excess iodine in aqueous $\mathrm{NaOH}$ and is completely converted to iodoform and sodium methanoate by $\mathrm{CH}{}_3\mathrm{CH}{}_2\mathrm{OH}+4\mathrm{I}{}_2+6\mathrm{NaOH}\to \mathrm{CHI}{}_3+\mathrm{HCOONa}+5\mathrm{NaI}+5\mathrm{H}{}_2\mathrm{O}$. Calculate the mass of $\mathrm{NaOH}$ consumed in grams. (Molar masses: ethanol 46, $\mathrm{NaOH}$ 40 g/mol.) Give the answer to the nearest integer.

Numerical answer type, answer in g, tolerance 0.5.