JEE Advanced levelSingle correct optionDifficulty 3 of 3bm134
At equilibrium, K=kf/kr for SP. An enzyme raises kf by a factor of 104 at constant temperature. By what factor does it change kr, and what is the new value of K relative to the old value?
Akr is unchanged and K increases by 104
Bkr decreases by 104 and K is unchanged
Ckr increases by 104 and K increases by 108
Dkr increases by 104 and K is unchanged
Answer: D
The equilibrium constant is fixed by thermodynamics and cannot be altered by a catalyst. Since K=kf/kr is constant, kr must rise by the same factor 104 as kf.