Answer: B, C, D
pI = (2.0+3.9)/2=2.95. At pH 7 (above pI) it is −1 and goes to the anode. At pH 12 both carboxyls are ionised and the amino group is free, net −2. At pH 2.0 (below the pI) the net charge is positive (about +0.5), so it goes to the cathode and the last statement is false.