JEE Advanced levelSingle correct optionDifficulty 3 of 3bn217
Arrange the average oxidation number of S in these species in INCREASING order: (i) SX2OX3X2−, (ii) SX4OX6X2−, (iii) SOX3X2−, (iv) SX2OX8X2− (one peroxo link, the two O-O oxygens at −1).
A(i), (ii), (iii), (iv)
B(ii), (i), (iii), (iv)
C(i), (iii), (ii), (iv)
D(iv), (iii), (ii), (i)
Answer: A
(i) 2x−6=−2, +2. (ii) 4x−12=−2, +2.5. (iii) x−6=−2, +4. (iv) six O at −2 and two at −1: 2x−14=−2, +6. Order: +2,+2.5,+4,+6.