MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Basic Inorganic Nomenclature and Oxidation Number
/
Formula from name and name from formula
JEE Advanced level
One or more correct options
Difficulty 3 of 3
bn205
Treat NO in nitroprusside as
NO
X
+
and CO as neutral. Select ALL correct name-oxidation-state pairs.
A
Na
X
2
[
Fe
(
CN
)
X
5
NO
]
: sodium pentacyanidonitrosylferrate(II)
B
K
X
4
[
Fe
(
CN
)
X
6
]
: potassium hexacyanidoferrate(II)
C
K
X
3
[
Fe
(
CN
)
X
6
]
: potassium hexacyanidoferrate(II)
D
Ni
(
CO
)
X
4
: tetracarbonylnickel(0)
Answer: A, B, D
Nitroprusside:
x
+
5
(
−
1
)
+
1
=
−
2
gives Fe = +2.
[
Fe
(
CN
)
X
6
]
4
−
has Fe = +2.
K
X
3
[
Fe
(
CN
)
X
6
]
:
x
−
6
=
−
3
, Fe = +3, so (II) is wrong. Ni in
Ni
(
CO
)
X
4
is 0.
Practice Basic Inorganic Nomenclature and Oxidation Number
More on Formula from name and name from formula
Previous question
Next question
More questions on Formula from name and name from formula
Select ALL correct name-formula pairs.
JEE Advanced level
Use F = -1, O = -2. In bleaching powder CaOCl2 take the structure Ca(OCl)Cl (one hypochlorite and one chloride). Select ALL correct statemen...
JEE Advanced level
Hydrogen is -1 in metal and boron/aluminium hydrides, and +1 elsewhere; Na and Li are +1, Cl is -1. Select ALL correct statements.
JEE Advanced level
Match the nitrogen compound (Column I) with the oxidation number of N (average, if more than one N atom; H = +1, O = -2) (Column II). Column...
JEE Advanced level
Arrange the average oxidation number of S in these species in INCREASING order: (i) S2O3^2-, (ii) S4O6^2-, (iii) SO3^2-, (iv) S2O8^2- (one p...
JEE Advanced level
With O = -2 and F = -1, xenon in which of these compounds has an oxidation number different from the others?
JEE Advanced level