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JEE Advanced levelSingle correct optionDifficulty 3 of 3bn216

Match the nitrogen compound (Column I) with the oxidation number of N (average, if more than one N atom; H = +1, O = $- 2$ ) (Column II). Column I: P $N X_{2} H X_{4}$ ; Q $NH X_{2} OH$ ; R $HN X_{3}$ ; S $N X_{2} O$ . Column II: 1 $- 1$ ; 2 $- 1/3$ ; 3 $- 2$ ; 4 $+ 1$ .

AP-3, Q-1, R-2, S-4
BP-1, Q-3, R-2, S-4
CP-3, Q-1, R-4, S-2
DP-3, Q-2, R-1, S-4

Answer: A

N X_{2} H X_{4}

:

2 x + 4 = 0

,

- 2

.

NH X_{2} OH

:

x + 3 - 2 = 0

,

- 1

.

HN X_{3}

:

1 + 3 x = 0

,

- 1/3

.

N X_{2} O

:

2 x - 2 = 0

,

+ 1

.

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