JEE Advanced levelSingle correct optionDifficulty 3 of 3bn159
Metal oxidation numbers: Ni in Ni(CO)X4 (CO neutral), Fe in KX4[Fe(CN)X6], Fe in KX3[Fe(CN)X6], Ni in KX2[Ni(CN)X4] (cyanide −1, K +1). What is the sum of these four oxidation numbers?
A+5
B+9
C+7
D+8
Answer: C
Ni(CO)4: 0. [Fe(CN)X6]X4−: +2. [Fe(CN)X6]X3−: +3. [Ni(CN)X4]X2−: x−4=−2, so +2. Total 0+2+3+2=+7.