In sodium nitroprusside, Na2[Fe(CN)5NO], treat the nitrosyl as NO+ and each cyanide as CN^-. What is the sum of the oxidation numbers of Fe and of the nitrosyl N atom (O is -2)?

JEE Advanced levelSingle correct optionDifficulty 3 of 3bn158

In sodium nitroprusside, $Na X_{2} [Fe (CN) X_{5} NO]$ , treat the nitrosyl as $NO X^{+}$ and each cyanide as $CN X^{-}$ . What is the sum of the oxidation numbers of Fe and of the nitrosyl N atom (O is $- 2$ )?

Fe:

2 (+ 1) + x + 5 (- 1) + 1 = 0

gives

x = + 2

. N in

NO X^{+}

n - 2 = + 1

gives

n = + 3

. Sum

= 2 + 3 = + 5