Arrange the Mn species by INCREASING oxidation number of Mn (use the AVERAGE for $\mathrm{Mn}{}_3\mathrm{O}{}_4$; K is $+1$, O is $-2$): (i) $\mathrm{KMnO}{}_4$, (ii) $\mathrm{K}{}_2\mathrm{MnO}{}_4$, (iii) $\mathrm{MnO}{}_2$, (iv) $\mathrm{Mn}{}_3\mathrm{O}{}_4$.

1. A(iv) < (iii) < (ii) < (i)
2. B(iii) < (iv) < (ii) < (i)
3. C(iv) < (iii) < (i) < (ii)
4. D(i) < (ii) < (iii) < (iv)