The ratio of the spin-only magnetic moment of Cr^2+ ion to that of a neutral Cr atom (both in ground state) is closest to

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The ratio of the spin-only magnetic moment of $Cr X^{2 +}$ ion to that of a neutral Cr atom (both in ground state) is closest to

Cr atom

3 d^{5} 4 s^{1}

has 6 unpaired electrons:

μ = 48

Cr X^{2 +}

3 d^{4}

with 4 unpaired:

μ = 24

. Ratio

= 24/48 = 0.707