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JEE Advanced levelSingle correct optionDifficulty 3 of 3as213

Among $Fe$ , $Mn X^{3 +}$ , $Cr X^{2 +}$ , $Ni$ and $Co X^{2 +}$ (all in ground state), the number of species having exactly the same number of unpaired electrons as $Fe X^{2 +}$ is

A2
B4
C1
D3

Answer: D

Fe X^{2 +}

is

3 d^{6}

: 4 unpaired. Fe

3 d^{6} 4 s^{2}

: 4;

Mn X^{3 +}

3 d^{4}

: 4;

Cr X^{2 +}

3 d^{4}

: 4; Ni

3 d^{8} 4 s^{2}

: 2;

Co X^{2 +}

3 d^{7}

: 3. Three species match.

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