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JEE Main levelNumerical answerDifficulty 2 of 3as208

Find the total number of unpaired electrons present in the ground-state atoms of Ti, V, Cr, Mn, Fe and Co taken together ( $Z = 22$ to $27$ ).

Numerical answer type, tolerance 0.1.

Answer: 23

Ti

3 d^{2} 4 s^{2}

: 2; V

3 d^{3} 4 s^{2}

: 3; Cr

3 d^{5} 4 s^{1}

: 6; Mn

3 d^{5} 4 s^{2}

: 5; Fe

3 d^{6} 4 s^{2}

: 4; Co

3 d^{7} 4 s^{2}

: 3. Total

= 2 + 3 + 6 + 5 + 4 + 3 = 23

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