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de Broglie wavelength and uncertainty principle
JEE Main level
Single correct option
Difficulty 2 of 3
as125
Using the Bohr model with
a
0
=
0.529
A
˚
, the de Broglie wavelength of the electron in the
n
=
2
orbit of hydrogen is closest to
A
6.65
A
˚
B
13.30
A
˚
C
3.32
A
˚
D
2.12
A
˚
Answer: A
Orbit circumference
=
nλ
, with
r
2
=
4
a
0
. So
λ
=
2
π
r
2
/2
=
2
π
×
4
×
0.529/2
=
6.65
A
˚
.
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