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de Broglie wavelength and uncertainty principle
JEE Main level
Single correct option
Difficulty 2 of 3
as122
An electron moves at
3.0
×
1
0
6
m
s
−
1
. Use
h
=
6.626
×
1
0
−
34
J
s
and
m
e
=
9.1
×
1
0
−
31
kg
. Its de Broglie wavelength is
A
0.4854
nm
B
0.0243
nm
C
2.43
nm
D
0.2427
nm
Answer: D
λ
=
h
/
(
m
e
v
)
=
6.626
×
1
0
−
34
/
(
9.1
×
1
0
−
31
×
3.0
×
1
0
6
)
=
0.2427
nm
.
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