An electron is accelerated from rest through 250 V. Use h = 6.626x10^-34 J s, m_e = 9.1x10^-31 kg, e = 1.6x10^-19 C. Find its de Broglie wavelength in pm, to the nearest integer.

JEE Main levelNumerical answerDifficulty 2 of 3as127

An electron is accelerated from rest through $250 V$ . Use $h = 6.626 \times 1 0^{- 34} J s$ , $m_{e} = 9.1 \times 1 0^{- 31} kg$ , $e = 1.6 \times 1 0^{- 19} C$ . Find its de Broglie wavelength in pm, to the nearest integer.

Numerical answer type, answer in pm, tolerance 1.

λ = h / 2 m_{e} e V = 6.626 \times 1 0^{- 34} / 2 \times 9.1 \times 1 0^{- 31} \times 1.6 \times 1 0^{- 19} \times 250 = 77.66 pm