An electron is accelerated from rest through a potential difference of 150 V. Using h = 6.626x10^-34 J s, m_e = 9.1x10^-31 kg and e = 1.6x10^-19 C, its de Broglie wavelength is nearest to

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An electron is accelerated from rest through a potential difference of $150 V$ . Using $h = 6.626 \times 1 0^{- 34} J s$ , $m_{e} = 9.1 \times 1 0^{- 31} kg$ and $e = 1.6 \times 1 0^{- 19} C$ , its de Broglie wavelength is nearest to

Kinetic energy

= e V

, so

λ = h / 2 m_{e} e V

. With the given values,

λ = 1.003 \overset{˚}{A}

, about

1 \overset{˚}{A}