JEE Advanced levelNumerical answerDifficulty 3 of 3as046
Atomic masses: X11X2121H=1.007825u, neutron =1.008665u, X816X28216O=15.994915u; 1u=931.5MeV/c2. Find the binding energy per nucleon of X816X28216O in MeV, to one decimal.
Numerical answer type, answer in MeV, tolerance 0.05.
Answer: 8 MeV
Mass defect = 8(1.007825) + 8(1.008665) - 15.994915 = 0.137005 u. Binding energy = 0.137005 x 931.5 = 127.62 MeV. Per nucleon = 127.62/16 = 7.976, i.e. 8.0 MeV.