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JEE Advanced levelNumerical answerDifficulty 3 of 3as046

Atomic masses: , neutron , ; . Find the binding energy per nucleon of in MeV, to one decimal.

Numerical answer type, answer in MeV, tolerance 0.05.

Answer: 8 MeV

Mass defect = 8(1.007825) + 8(1.008665) - 15.994915 = 0.137005 u. Binding energy = 0.137005 x 931.5 = 127.62 MeV. Per nucleon = 127.62/16 = 7.976, i.e. 8.0 MeV.
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