Answer: D
Ionisation gives the tertiary benzylic cation CHX3−CX+(Ph)X− next to C(OH)(CHX3)Ph. Phenyl migrates in preference to methyl, so the neighbouring carbon becomes C=O with its methyl left behind and the cationic carbon becomes C(CHX3)(Ph)X2. The product is CHX3CO−C(CHX3)(CX6HX5)X2, 3,3-diphenylbutan-2-one.