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JEE Advanced levelSingle correct optionDifficulty 3 of 3ap052

A compound of formula $C X_{8} H X_{10} O$ liberates $H X_{2}$ with sodium, does not dissolve in aqueous $NaOH$ , gives no colour with neutral $FeCl X_{3}$ , and gives a yellow precipitate with $I X_{2}$ / $NaOH$ . The compound is

A2-phenylethan-1-ol
B1-phenylethan-1-ol
C4-ethylphenol
Dethoxybenzene

Answer: B

The O-H group (reaction with Na) without phenol behaviour points to an alcohol. A positive iodoform test needs

CH X_{3} CH (OH) X^{-}

, so it is

C X_{6} H X_{5} - CH (OH) - CH X_{3}

. 2-Phenylethanol lacks that unit, 4-ethylphenol is a phenol, and ethoxybenzene has no O-H.

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