A galvanic cell with n = 2 has E deg_cell = 0.46 V at 298 K. Using F = 96500 C mol^-1 and 2.303RT/F = 0.0591 V, the values of Delta G deg and the equilibrium constant for the cell reaction are nearest to

Delta G deg = -88.8 kJ mol^-1, K = 3.7 x 10^15

Delta G deg = 88.8 kJ mol^-1, K = 2.7 x 10^-16

Delta G deg = -44.4 kJ mol^-1, K = 6.1 x 10^7

Delta G deg = -88.8 kJ mol^-1, K = 6.1 x 10^7

JEE Advanced levelSingle correct optionDifficulty 3 of 3td217

A galvanic cell with $n = 2$ has $E_{cell}^{\circ} = 0.46 V$ at $298 K$ . Using $F = 96500 C mo l^{- 1}$ and $2.303 RT / F = 0.0591 V$ , the values of $Δ G^{\circ}$ and the equilibrium constant for the cell reaction are nearest to

Δ G^{\circ} = - n F E^{\circ} = - 2 \times 96500 \times 0.46 = - 88780 J mo l^{- 1}

. Also

lo g K = n E^{\circ} /0.0591 = 0.92/0.0591 = 15.567

, so

K = 3.7 \times 1 0^{15}

. Forgetting

n

halves both quantities in the log.