Half a mole of nitrogen (treated as a rigid diatomic ideal gas, C_V = tfrac52R) in a rigid vessel is heated from 300 K to 450 K. Taking R = 8.314 J mol^-1K^-1, the heat absorbed is nearest to

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Half a mole of nitrogen (treated as a rigid diatomic ideal gas, $C_{V} = \frac{5}{2} R$ ) in a rigid vessel is heated from $300 K$ to $450 K$ . Taking $R = 8.314 J mo l^{- 1} K^{- 1}$ , the heat absorbed is nearest to

The volume is constant so

q_{V} = n C_{V} Δ T = 0.5 \times 2.5 \times 8.314 \times 150 = 1558.9 J

, about 1559 J. Using

C_{P}

instead would be wrong because the vessel is rigid.