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JEE Main levelNumerical answerDifficulty 2 of 3td179

Three moles of a diatomic ideal gas ( $C_{P} = \frac{7}{2} R$ ) are heated from $300 K$ to $400 K$ at constant pressure. Taking $R = 8.314 J mo l^{- 1} K^{- 1}$ , find the heat absorbed in kJ (two decimals).

Numerical answer type, answer in kJ, tolerance 0.01.

Answer: 8.73 kJ

At constant pressure

q_{P} = n C_{P} Δ T = 3 \times 3.5 \times 8.314 \times 100 = 8729.7 J = 8.73 kJ

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