Two moles of an ideal gas expand reversibly and isothermally at $300 K$ from $2.0 L$ to $10.0 L$ . Using $R = 8.314 J mo l^{- 1} K^{- 1}$ and $ln 5 = 1.609$ , calculate the magnitude of the work done by the gas in $kJ$ (two decimals).

Numerical answer type, answer in kJ, tolerance 0.02.

Answer: 8.03 kJ

For reversible isothermal expansion

∣ w ∣ = n RT ln (V_{2} / V_{1})

∣ w ∣ = 2 \times 8.314 \times 300 \times 1.609 = 8.03 kJ