JEE Main levelNumerical answerDifficulty 2 of 3td122
Two moles of a monatomic ideal gas are heated at constant pressure from 300K to 400K. Taking R=8.314Jmol−1K−1, calculate ΔU of the gas in joules (nearest integer).
Numerical answer type, answer in J, tolerance 1.
Answer: 2494 J
For an ideal gas ΔU=nCVΔT for any process, with CV=23R for a monatomic gas. ΔU=2×1.5×8.314×100=2494.2J, i.e. about 2494 J.