One mole of a monoatomic ideal gas is at $2.00 bar$ and $10.0 L$ . For infinitesimal reversible changes from this state, select the correct statement(s).

AThe adiabat and isotherm have the same slope at this point
BThe slope of the isotherm, $d P / d V$ , is $- 0.200 bar L^{- 1}$
CFor a small volume increase the pressure falls more along the adiabat than along the isotherm
DThe slope of the adiabat, $d P / d V$ , is $- 0.333 bar L^{- 1}$

Answer: B, C, D

Isotherm:

P V =

const gives

d P / d V = - P / V = - 0.200 bar L^{- 1}

. Adiabat:

P V^{γ} =

const gives

d P / d V = - γ P / V = - 0.333 bar L^{- 1}

with

γ = 5/3

. Because

γ > 1

the adiabat is steeper, so the pressure drops faster along it.